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7k^2+23k+8=0
a = 7; b = 23; c = +8;
Δ = b2-4ac
Δ = 232-4·7·8
Δ = 305
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{305}}{2*7}=\frac{-23-\sqrt{305}}{14} $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{305}}{2*7}=\frac{-23+\sqrt{305}}{14} $
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